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    K_"sp" is given by the ion product we gets K_"sp"=3 33xx10^-25 We set up the solubility equilibrium Cr (OH)_3 (s)rightleftharpoonsCr^ (3+) + 3HO^- Where K_"sp"= [Cr^ (3+)] [HO^-]^ (3) But we have been given [HO^-]=4xx10^-6*mol*L^-1 Now for a saturated solution, WE KNOW from the stoichiometry that [Cr^ (3+)]=1 3 [HO^-] And so we substitute this value back into the K_"sp
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    8(1+t)" Js"^-1 We know that Kinetic Energy of an object having mass m and velocity v is given by the expression KE=1 2mv^2 (1) Also kinematic equation connecting quantities of interest is v=u+at (2) where u is initial velocity, a and t are acceleration and time respectively Inserting value of v from (2) in (1) we get KE=1 2m(u+at)^2 To find rate of change of kinetic energy we
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